Question

40% passenger from a train got down st station A . 60% of remaining passengers got down at station B . if there were still 540 passengers in the train, how many passengers were there before station And B​

Answer 1

Answer:

2250

Step-by-step explanation:

let total passenger was x

at station A passengers got down 

x \: of40 \: \% = x \times \frac{40}{100 } = \frac{2x}{5}xof40%=x×10040=52x 

now remaining 

x - \frac{2x}{5} = \frac{3x}{5}x−52x=53x 

at station B passengers got down

\frac{3x}{5} \: of \: 60\% = \frac{3x}{5} \times \frac{60}{100} = \frac{9x}{25}53xof60%=53x×10060=259x 

now remaining 

\frac{3x}{5} - \frac{9x}{25 } = \frac{6x}{25}53x−259x=256x 

now, 

\begin{gathered}\frac{6x}{25} = 540 \\ or \: 6x = 540 \times 25 \\ or \: x = \frac{25 \times 540}{6} = 2250\end{gathered}256x=540or6x=540×25orx=625×540=2250 

so there were 2250 passengers

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Answer 2

Answer:

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