Question

40% passenger from got down at station A. 60% of the remaining passengers got down at station b. If there were still 540 passengers in the train at station A and station B?​

Answer 1

Correct Question:

40% passengers from a train got down at station A, 60% of the remaining passengers got down at station B. if there were still 540 passengers in the train, how many passengers were before station A provided no one boarded the train at station. A and station B.

Solution :

Let the Total no passenger's be x

According to the Question :

At station A , 40% passengers from a train got down.

So, Number of passenger got down At station A$\sf=40\%\:of\:x$

$\sf=\dfrac{40}{100}\times\:x=\dfrac{2x}{5}$

Remaining passengers

$\sf=x-\dfrac{2x}{5}$

$\sf=\dfrac{5x-2x}{5}$

$\sf=\dfrac{3x}{5}$

Now , At station B , 60% of the remaining passengers got down . thus ,

So, Number of passenger got down at station B=

Remaining$\sf=60\%\:of\dfrac{3x}{5}$

$\sf=\dfrac{60}{100}\times\dfrac{3x}{5}$

$\sf=\dfrac{9x}{25}$

Now , Remaining passengers after station B

$\sf=\dfrac{3x}{5}-\dfrac{9x}{25}$

$\sf=\dfrac{6x}{25}$

But , it's given that there were still 540 passengers in the train , then

$\sf\dfrac{6x}{25}=540$

$\sf6x=540\times25$

$\sf6x=13500$

$\sf\:x=\dfrac{13500}{6}$

$\sf\:x=2250$

Therefore , 2250 passengers were before station A provided no one boarded the train at station A and station B.