Question

40% passengers from a train got down at station A, 60% of the remaining passengers got down at station B. if there were still 540 passengers in the train, how many passengers were before station A provided no one boarded the train at station. A and station B.

Answer 1

let total passenger was x
at station A passengers got down
$x \: of40 \: \% = x \times \frac{40}{100 } = \frac{2x}{5}$
now remaining
$x - \frac{2x}{5} = \frac{3x}{5}$
at station B passengers got down
$\frac{3x}{5} \: of \: 60\% = \frac{3x}{5} \times \frac{60}{100} = \frac{9x}{25}$
now remaining
$\frac{3x}{5} - \frac{9x}{25 } = \frac{6x}{25}$
now,
$\frac{6x}{25} = 540 \\ or \: 6x = 540 \times 25 \\ or \: x = \frac{25 \times 540}{6} = 2250$
so there were 2250 passengers

Answer 2

Answer: 2250

Step-by-step explanation:

Let total number of passengers were before station A = x

Now according question 40% of passenger got down

So, Number of passenger got down At station A=    $40\% \text{ of } x =\dfrac{40}{100}\times x = \dfrac{2x}{5}$

Remaining passengers  =    $x - \dfrac{2x}{5}=\dfrac{3x}{5}$

Now,  60% of remaining got down at station B

So, Number of passenger got down at station B=  $60\% \text{ of }{\dfrac{3x}{5} } = \dfrac{60}{100}\times\dfrac{3x}{5} = \dfrac{9x}{25}$

Remaining passengers after station B = $\dfrac{3x}{5} -\dfrac{9x}{25} =\dfrac{6x}{25}$

But as given in question remaining passengers are 540

So,  

    $\dfrac{6x}{25} =540\\\\\Rightarrow 6x=540\times25\\\\ \Rightarrow x= \dfrac{540\times25}{6} =2250$

So there were 2250 passengers before station A