40 percent of the passenger from a bus got off at station A, 75 percent of the remaining got off at station B. If the remaining 12 passenger were taken to station C, find the original number of passenger.
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Answer:
number of the remaining passengers left after 40 percent of the actual passengers = 12*4 = 48
48 = the 60 percent of the actual passengers
therefore, 10 percentage = 48/6 = 8
100 percentage = 60% + 40%
=48 + ( 4*8)
= 48 + 32 = 80
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