Math, asked by mudit11, 1 year ago

## 40 POINTS ##

• Basic Integration

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Answered by Anonymous
5
Your Answer is Attached :)

Formula I Used Which I Didn't Mentioned in Pic are

 \huge \cos(2x) = \cos^{2} (x) - \sin^{2} (x)

 \huge \cot(x) = \frac{ \cos(x) }{ \sin(x)}

 \huge \bf {\fbox{ \red{thanks}}}
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Answered by brunoconti
3

Answer:

Step-by-step explanation:

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