Question

(40 points) find the value of K​

Answer 1

                                                                                                                             

given ΔABC , PQ parallel to BC

so, $\frac{AP}{PB} = \frac{AQ}{QC}$                                               $(thales thearom)$

$\frac{k}{2k + 2} = \frac{k + 3}{2k + 9}$

$(k)(2k + 9) = (2k + 2)(k + 3)$

$2k^2 + 9k = 2k^2 + 6k + 2k + 6$

$9k - 8k = 6$

$k = 6$

                                                                                                                             

Answer 2

certain specialised crops began to be grown not for consumption in village but for sale in national and even in international market.