Question

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Answer 1

Answer:

b)12√2 N

Explanation:

see the attachments for the free body diagrams,

T=2a.....equ(i). from 1st fbd

30-T=3a.....equ(ii). from 3rd fbd

adding them we get,

30=5a

a=6 m/s²

thus,

T=2*6=12 m/s²

from 2nd fbd,

the net magnitude of the net force=T√2

=12√2 N

Answer 2

Answer:

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