Question

40 Sweets are distributed between ramu and Somu in the ratio of 2:3. How much does each get?​

Answer 1

Answer:

16 , 24

Step-by-step explanation:

Given 40 Sweets are distributed between ramu and Somu in the ratio of 2:3

So, Ramu got 40 × (2/5) sweets = 16 sweets

and Somu got 40 × (3/5) sweets = 24 sweets

Answer 2

Given,

$40$ sweets are distributed between ramu and somu in the ratio of $2:3$

Here, we have to find how much does each get

Let the ratio of ramu and somu be $2x:3x$

The total ratio of ramu and somu is equal to the total sweets

$2x+3x=40$

Here, we have to find the value of $x$,

$5x=40$

$x= \frac{40}{5}$

$x= 8$

We have to substitute $x=8$ in $2x$ and $3x$, we get individual count of sweets

$2x=2\times8$

$= 16$

$3x=3\times8$

$=24$

Therefore, ramu get $16$ sweets and somu get $24$ sweets.