Question

40. The earth (mass = 6 x 1024 kg) revolves around
the sun with an angular velocity of 2 * 10- rad/s
in a circular orbit of radius 1.5 x 108 km. The force
exerted by the sun on the earth, in newtons, is
(1) 36 × 1021
(2) 27 x 1039
(3) Zero
(4) 18 x 1025​

Answer 1

Explanation:

Force exerted by sun of earth =MW2R

given M=6×1024kg

W=2×10−7 rod/s

R=1.5×108km

F=(6×1024)(2×10−7)2(1.5×108×103)

    =36×1021N.....