Question

40. The radius and height of a right circular cone are 6 cm and 7 cm respectively. The
volume of the cone is​

Answer 1

EXPLANATION.

The radius of the right circular cone = 6

The height of the right circular cone = 7

To find the volume of the cone.

According to the question,

Formula of the right circular cone

=> ⅓πr²h

=> 1/3 X 22/7 X 6X 6 X 7

=> 264 cm³

=> volume of the cone = 264 cm³.

SOME RELATED FORMULA.

$\sf \to \: volume \: of \: cuboid \: = l \times b \times h \\ \\ \sf \to \: volume \: of \: cube \: = {a}^{ 3} \\ \\ \sf \to \: volume \: of \: cylinder \: = \pi \: {r}^{2} h \\ \\ \sf \to \: volume \: of \: cone \: = \dfrac{1}{3}\pi \: r^2h \\ \\ \sf \to \: volume \: of \: sphere \: = \dfrac{4}{3} \pi \: {r}^{3} \\ \\ \sf \to \: volume \: of \: hemisphere \: = \dfrac{2}{3} \: \pi \: {r}^{3}$

Answer 2

Answer:

The volume of cone is 264 cm²

Step-by-step explanation:

$\dashrightarrow\tt\:\: Volume_{{\tiny (of\:cone)}}= \dfrac{1}{3} \pi r^{2} h$

$\dashrightarrow\tt\:\: Volume_{{\tiny (of\:cone)}}= \dfrac{1}{ \cancel{3}} \times \dfrac{22}{ \cancel{7}} \times \cancel{ 6 } \times 6 \times \cancel{7}$

$\dashrightarrow\tt\:\:Volume_{{\tiny (of\:cone)}}= 22 \times 2 \times 6$

$\dashrightarrow\tt\:\:Volume_{{\tiny (of\:cone)}}= 44 \times 6$

$\dashrightarrow \underline{ \boxed{\tt\: \: Volume _{{\tiny (of\:cone)}}=264 \: {cm}^{2} }}$

_______________________

$\bigstar\:\underline{\textbf{Formulae Related to Cone :}}$

$\sf {\footnotesize\textsf{1)}} \: \:Area\:of\:Base =\pi r^2$

$\sf {\footnotesize\textsf{2)}} \: \:\:CSA = \pi rl$

$\sf{\footnotesize\textsf{3)}} \:\:TSA = Area\:of\:Base + CSA \\ {\quad=\pi r^2+\pi rl}$

$\sf{\footnotesize\textsf{4)}} \: \:Volume=\dfrac{1}{3}\pi r^2h$