40. The rate of a reaction doubles when the temperature changes from 300 K to 310 K.
Activation energy for the reaction is
(R = 8.314 J K-1 mol-1 : log 2 – 0.3010)
(A) 60.5 kJ mol (B) 53.6 kJ mol-1 (C) 48.6 kJ mol-1 (D) 58.5 kJ mol!
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Activation energy of such a reaction will be (R = 8.314 JK–1 mol–1 and log 2 = 0.301). 53.6 kJ mol-1 ... Given, T2 = 310; T1 = 300K ... the rate = k[A] [B]2 with k = 2.0 x 10–6 mol–2L2s–1 .
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