Question

40
The sum of three consecutive multiples of 7 is 189. The numbers are
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Answer 1

Answer:

Let the three multiples be 7x,7x+7and 7x+14

7x+7x+7+7x+14=63

21x+21=63

21x=63-21

x=42/21

x=2

so...

7x=14

7x+7=21

7x+14=28

Step-by-step explanation:

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Answer 2

Answer:

56,63,70

Step-by-step explanation:

let no.be x, x+7, x+14

x+x+7+x+14=189

3x+21=189

3x=189-21

3x=168

x=168/3

x=56

three consecutive no. are

x = 56

x+7 =63

x+14 =70

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