Question

40. Two chords AB and CD of a circle intersect
each other at a point E outside the circle. If
18 - 11 cm, B = 3 cm and DE = 3,5 cm, then
CD?
1) 10,5 dm
(b) 9,5 cm
10) 8.5em
(d) 7.5 cm​

Answer 1

Answer:

we know that when two chords of a circle intersect either inside or out side then the area of the rectangle formed by the segments of one chord is equal to the area of the rectangle formed by the segments of the other.

So in this let CD = x cm

Then AE × BE = CE × DE

ie. 14×3 = (x+3.5)×3.5

So x+3.5 = 14×3/3.5 => x+3.5 = 4×3

So x= 12 - 3.5 = 8.5. so CD = 8.5 cm