40) Two numbers x and y such that x + y = 2
maximum are
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Answers
Answered by
60
Step-by-step explanation:
ANSWER
Let P=xy
3
It is given that x+y=60
⇒x=60−y
P=(60−y)y
3
[Putting value of x]
=60y
3
−y
4
⇒
dy
dP
=180y
2
−4y
3
dy
2
d
2
P
=360y−12y
2
For maximum or minimum values of y, P we have
dy
dP
=0
⇒180y
2
−4y
3
=0
⇒4y
2
(45−y)=0
⇒y=0 45−y=0 y=45
Now (
dy
2
d
2
P
)
y=45
=360×45−12(45)
2
=12×45−(30−45)
=−8100<0
P is maximum when y=45
when y=45 x+y=60 ⇒x=60−45
x=15
Numbers are 15 and 45
hope it helps you
thanks
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Answered by
67
above one is Excellent answer ☝
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