Question

40. Two poles of 19m and 1lm stand upright in a playground. If the distance between their
tops is 17m, find how far apart are their feet placed in the ground
With explanationpls.​

Answer 1

Answer:

15m

Step-by-step explanation:

Please refer the attached image for more clarity.

In the figure, we need to find out the d

By using pythagoras theorem for right angled triangle

${hypotenuse}^{2} = {base}^{2} + {height}^{2} \\ {d}^{2} = {b}^{2} + {(y - x)}^{2}$

Solve by putting the values

${17}^{2} = {b}^{2} + {(19 - 11)}^{2} \\ {b}^{2} = 289 - {8}^{2} \\ {b}^{2} = 289 - 64 = 225 \\ b = \sqrt{225} = 15$

Hence, the feet of the poles are 15m apart.