Question

40) What is the missing term in the given series?
1/4, 1/8, 1/16, _ 1/64
ar
e
e
A) 1/22
By 1/32
C) 1/24
D) 1/34​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

The missing term in the given series

1/4, 1/8, 1/16, _ 1/64

A) 1/22

B) 1/32

C) 1/24

D) 1/34

EVALUATION

Here the given series is

$\displaystyle \sf{ \frac{1}{4} \: ,\: \frac{1}{8} \: , \: \frac{1}{16} \: , \: ? \: , \: \frac{1}{64} }$

This is a Geometric Progression with

$\displaystyle \sf{ First \: term = a = \frac{1}{4} }$

$\displaystyle \sf{ Common \: Ratio = r = \frac{1}{2} }$

Hence fourth term

$\displaystyle \sf{ = \frac{1}{16} \times \frac{1}{2} = \frac{1}{32} }$

FINAL ANSWER

Hence the correct option is

$\displaystyle \sf{ B) \: \: \frac{1}{32} }$

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Answer 2

Given :  series  

1/4, 1/8, 1/16,  ?  ,  1/64

To Find : Missing term

A) 1/22

B) 1/32

C) 1/24

D) 1/34​

Solution:

1/4, 1/8, 1/16,  ?  ,  1/64

This is an GP

a = 1/4

r  = 1/2

1/4

1/4 x 1/2 = 1/8

1/8 x 1/2 = 1/16

1/16 x 1/2  = 1/32

1/32 x 1/2 = 1/64

Hence missing term = 1/32

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