40. What power is required to hoist 108 kg of coal per hour
from a mine which is 60 m deep?
[Takeg- 10 m
Answers
Given data :
- Mass of coal = 108 kg
- Depth of mine = 60 m
- Time taken to hoist coal = 1 hour = 60 min = 3600 sec
To find : Power is required to hoist 108 kg of coal per hour ?
Solution : Now by formula of potential energy which require to pull 108 kg load.
⟹ Potential energy = m * g * h
{where, g is gravitational force}
Let, depth of mine be height, h
⟹ Potential energy = 108 * 10 * 60
⟹ Potential energy = 1080 * 60
⟹ Potential energy = 64800 joule
Now, by formula of power :
⟹ Power = work done/time
{we know, work done = Potential energy}
⟹ Power = potential energy /time
⟹ Power = 64800/3600
⟹ Power = 18 watt
Answer : Hence, the 18 watt power is required to hoist 108 kg of coal per hour from a mine which is 60 m deep.
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