Question

40. Which of the following are the factors of 16x^4 - 81. [Select the correct alternatives) (1) (4x + 9) (4x - 9) (2) (4x2 + 9) (4x2 - 9) (3) (4x2 + 9) (2x + 3) (2x - 3) (4) (2x + 3)2 (2x - 3)​

Answer 1

Answer:

$(2x-3)(2x+3)$

Step-by-step explanation:

$16x^{4} -81\\= (2x^{2})^{2} - (3^{2} )^{2} \\= (2x-3)(2x+3)$