Question

40 + x +40x/100
= 12
find the value of x ?​

Answer 1

$\fbox{ANSWER} \\ \\ 40 + x + \frac{40x}{100} = 12 \\ \\ x + \frac{40x}{100} = 12 - 40 \\ \\ \frac{140x}{100} = ( - 28) \\ \\ 140x = - 2800 \\ \\ x = \frac{ - 2800}{140} \\ \\ x = - 20$

Answer 2

Answer:

x+10040x=12−40100140x=(−28)140x=−2800x=140−2800x=−20

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