Question

400 cm3 of a gas are compressed to half of its volume by applying a pressure of 0.5 atm. During the process 6.5 J of heat flows out to the surroundings. Calculate ∆E of the system.

Answer 1

$\huge\mathfrak\pink{i \: hope\: this\:helps\:u}$

Answer 2

∆E of the system is +3.63 Joules

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=$-P\Delta V=-P(V_2-V_1)$

P= 0.5 atm , $V_2$ = 400 ml= 0.4 L    (1L=1000ml)

$V_1$ = 200 ml =0.2 L

w = =$-0.5atm\times (0.2-0.4)L=0.1Latm=10.13Joules$  {1Latm=101.3J}

q = -6.5 J   {Heat released by the system is negative}

$\Delta E=-6.5J+(10.13)J=3.63J$

Learn more about first law of thermodynamics:

https://brainly.in/question/8498703

brainly.in/question/8247936