Question

400 g of aluminium hydroxide is dissolved in 750 ml of water. what is the molarity and normality class 11 ncert​

Answer 1

To find:-

Molarity = ?

and Normality = ?

Formula:-

$molarity = \frac{number \: of \: moles \: of \: solute}{volume \: of \: solution(litre)}$

$normality = \frac{number \: of \: gram \: equivalents \: of \: solute}{volume \: of \: solution(litre)}$

$normality = molarity \times valency \: factor$

Solution:-

Given,

400g of Al(OH)3 is dissolved in 750ml of water .

Volume = 750ml = 0.75 Litre

Valency factor of “Al(OH)3” = 3 .

Molecular weight of “Al(OH)3” = 78g .

mole of Al(OH)3

$= \frac{400}{78} mol$

So,

Molarity

$= \frac{ \frac{400}{78} }{0.75}$

= 6.83 M

and Normality

$= 6.83 \times 3$

= 20.51 N .

Hope it's helpful to you.

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