Question

400 grams of water at 100 degrees celcius is mixed wirh 200 grams of water 40 degrees celcius.find the final temparature of rhe mixture

Answer 1

Answer:

80

Explanation:

Let the final temperature be T degree Celsius

Here

400*1*(100-T)=200*1*(T-40)

2(100-T)=T-40

200-2T=T-40

3T=240

T=80 degree Celsius

Answer 2

Answer:

b) 80 degrees Celsius

ok