Question

400 grams of water at 30 degree celsius is mixed with 600 grams of water at 30 degrees find the restulant temperature of the mixture​

Answer 1

Answer:30°C

Explanation:

m1=400g=0.4kg

m2=600g=0.6kg

t1=30°C

s=4200j/kg/°C

t2=30°C

t=?

then,

heat gained =heat loosed

m1*s*dt=m2*s*dt

0.4*4200*(t-30)=0.6*4200*(30-t)

0.4t-12=18-0.6t

0.4t+0.6t=18+12

∴t=30°C