400 joules of heat is produced per second and 16 ohm resistor. Find the potential difference across the resistor. second questiontwo metals which are all add with iron to make stainless steel.
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HEY!!
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▶️▶️When a current of I amperes passes through a circuit of resistance R ohms for a time of t seconds then the heat produced is given by the relation:
➡️H=I2Rt
▶️The above relation is known as the Joule’s law of heating.
➡️Given,
➡️Heat developed, H = 400 J
➡️Time, t = 1 s
➡️Resistance, R = 16 Ω
➡️H = I2Rt
➡️H = (V/R)2Rt
➡️H = V2t/R
➡️V2 = HR/t
➡️V2 = (400)(16)/1
➡️V = 80 V
⏩This is the potential difference across the resistance.
______________________________
▶️▶️When a current of I amperes passes through a circuit of resistance R ohms for a time of t seconds then the heat produced is given by the relation:
➡️H=I2Rt
▶️The above relation is known as the Joule’s law of heating.
➡️Given,
➡️Heat developed, H = 400 J
➡️Time, t = 1 s
➡️Resistance, R = 16 Ω
➡️H = I2Rt
➡️H = (V/R)2Rt
➡️H = V2t/R
➡️V2 = HR/t
➡️V2 = (400)(16)/1
➡️V = 80 V
⏩This is the potential difference across the resistance.
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