400 kg truck is moving with a velocity 40 kilometre per hour it is top 25 Metro beyond the point at which the brakes are applied find the retarding force
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Correct Question :-
- A truck of mass 400 kg is moving with a velocity of 40 km/h. If on applying brakes, the truck stops after coming to a distance of 25 m, find the retarding force?
Given :-
- Mass = m = 400 kg
- Initial Velocity = u = 40 km/h
- Final velocity = v = 0 ( Since it will come at rest )
- Distance = s = 25 m
To Find :-
- Retarding force = ?
Solution :-
3rd Equation of motion :-
⇾ v² - u² = 2as
⇾ 0² - 40² = 2 × a × 25
⇾ -1600 = 50a
⇾ a = 1600/50
⇾ a = -32 m²
Hence distance covered is -32 m².
Now,
➲ Force = Mass × Acceleration
➲ F = 400 × -32
➲ F = -12800 N
▪️Negative sign shows force against direction of motion.
Hence,
Retarding force = 12800 N ☑
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