Question

400 ml of nitrogen gas at 700 mm and 300 ml of hydrogen gas at 800 mm were introduced into a vessel of 2 litres at the same temp. calculate the final pressure of the gas mixture.

Answer 1

Answer:- Final pressure of gas mixture is 260 mmHg.

Solution:- It's Boyle's law as temperature is constant and pressure changes as the volume is changed.

Using Boyle's law we could calculate the new pressure for both the gases and finally using Dalton's law of partial pressures we could calculate the total pressure of the gas mixture.

For Boyle's law, the equation is:

$P_1V_1=P_2V_2$

For nitrogen gas, 700mmHg(400mL) = $P_2(2000mL)$

On rearranging the above for $P_2$ :

$P_2=(\frac{700mmHg*400mL}{2000mL})$

$P_2$ = 140mmHg

Similarly for hydrogen gas, $800mmHg(300mL)=P_2(2000mL)$

On rearranging the above equation:

$P_2=\frac{800mmHg(300mL)}{2000mL}$

$P_2$ = 120 mmHg

Now let's uase Dalton's law equation to calculate the final pressure of the gas mixture.

Total pressure = partial pressure of nitrogen + partial pressure of hydrogen

total pressure = 140 mmHg + 120 mmHg = 260 mmHg

So, the final pressure of the gas mixture would be 260 mmHg.

Answer 2

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