Question

4000 active nuclei of a radioactive material are present at t is equal to to zero after 60 minute 500 active nuclei are left in the sample the decay constant of the sample is​

Answer 1

Final answer: Decay constant of the sample is 0.03466 minute⁻¹.

Given that: We are given 4000 active nuclei of a radioactive material are present at t =0 after 60 minute 500 active nuclei are left in the sample.

To find: We have to find the decay constant of the sample.

Explanation:

• Radioactive disintegration is the emission of energy in the form of ionising radiation, the radioactive atom or radionuclide transform to different nuclide.
• Radioactive disintegration is first order kinetics.
• The rate of decay can be followed by noting the activity/amount of radioactive material in the sample at regular intervals.

• Decay constant, λ = $\frac{2.030}{t}$ ㏒$\frac{N_{t} }{N_{0}}$

Where,

N₀ = Number of atoms / activity / amount of radioactive species initially present.

$N_{t}$ = Number of atoms / activity / amount of the species present at time t.

t = Time

• Here,

N₀ = 4000

$N_{t}$ = 500

t = 60 minute

• Decay constant, λ = $\frac{2.030}{60}$ ㏒$(\frac{4000}{500})$

λ = $\frac{2.030}{60}$ ㏒$(\frac{40}{5})$ =  $\frac{2.030}{60}$ ㏒(8)

λ = $\frac{2.030}{60}$ ㏒ $(2^{3})$ = $(\frac{2.030}{60})$ * 3㏒2

λ = (0.03466) minute⁻¹

• Hence, the decay constant of the sample is 0.03466 minute⁻¹.

To know more about the concept please go through the links

https://brainly.in/question/15347561

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