400g of vegetable oil of specific heat capacity 1.98J/gºC is cooled from 100°C. Find final temperature if the heat energy given out by oil is 47376J
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Explanation:
Given , m=400g,θ1=1000C,θ2=? , specific heat of vegetable oil c=1.98J/g−oC,Q=47376J
Now , by the definition of specific heat c ,
Q=mcΔθ=mc(θ1−θ2)
or 47376=400×1.98(100−θ2)
or (100−θ2)=47376/(400×1.98)=59.8
or θ2=100−59.8=40.2oC
hope this helps
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