400g solution having 20%(w/w) solute is cooled then 50g solute precipitated. What is the %(w/w) of solute in remaining solution?
Answers
Answer : The %(w/w) of solute in remaining solution is, 8.57%
Explanation :
First we have to calculate the mass of solute.
Now we have to calculate the mass of remaining solution.
The mass of remaining solution = Total mass of solution - Mass of precipitated solute
The mass of remaining solution = 400 - 50 = 350 g
The mass of remaining solute = 80 - 50 = 30 g
Now we have to calculate the %(w/w) of solute in remaining solution.
Therefore, the %(w/w) of solute in remaining solution is, 8.57%
Answer : The %(w/w) of solute in remaining solution is, 8.57%
Explanation :
First we have to calculate the mass of solute.
Mass\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100Mass%=
Mass of solution
Mass of solute
×100
20\%=\frac{\text{Mass of solute}}{400g}\times 10020%=
400g
Mass of solute
×100
\text{Mass of solute}=80gMass of solute=80g
Now we have to calculate the mass of remaining solution.
The mass of remaining solution = Total mass of solution - Mass of precipitated solute
The mass of remaining solution = 400 - 50 = 350 g
The mass of remaining solute = 80 - 50 = 30 g
Now we have to calculate the %(w/w) of solute in remaining solution.
\%(w/w)\text{ of solute}=\frac{\text{Mass of solute}}{\text{Mass of remaining solution}}\times 100%(w/w) of solute=
Mass of remaining solution
Mass of solute
×100
\%(w/w)\text{ of solute}=\frac{30g}{350g}\times 100=8.57\%%(w/w) of solute=
350g
30g
×100=8.57%
Therefore, the %(w/w) of solute in remaining solution is, 8.57%