Question

400gram package lying on a horizontal surface is attached to a horizontal string which passes over a smooth pulley. When a mass of 200grams is attached to the other end of the string, the package is on the point of moving. Find , the coefficient of friction. i will mark the person brainliest etc etc

Answer 1

M1*g = 0.4 * 9.8 = 3.92 N. = Wt. of pkg.= Normal force(Fn).

Fp = 3.92*sin 0 = 0 = Force parallel to the surface.

!@#$%^& = M2*g = 0.2 * 9.8 = 1.96 N. = Force applied.

Fs = us*Fn. = 3.92us.

!@#$%^&-Fp-Fs = M*a.

1.96-0-3.92us = M*0 = 0, us = 0.50.