40g naoh is dissolved in water to form 1l naoh solution find out the molarity
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1
the volume of naoh= 1litre
the mass of nai= 40 grams
therefore, the mole number of naoh= 40÷23=1.7839
therefore, the molarity of naoh solution is = 1.7839
the mass of nai= 40 grams
therefore, the mole number of naoh= 40÷23=1.7839
therefore, the molarity of naoh solution is = 1.7839
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Given mass is 40g and molar mass of NaOH is 23+16+1=40
No of moles=given mass/molar mass
No of moles=40/40=1
Molarity=no of moles/1l of solution
So molarity is 1M
No of moles=given mass/molar mass
No of moles=40/40=1
Molarity=no of moles/1l of solution
So molarity is 1M
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