40g of hot water is poured in 100g of cold water,when the temperature of cold water rises by 10°C. If the temperature of hot water is 60°C,calculate the initial temperature of cold water.
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The initial temperature of cold water is :
• Let required temperature be T and intial temperature of cold water is Tc.
• Given : mass of hot water, Mh = 60g
mass of cold water, Mc = 100g
Temperature of cold water rises, T - Tc = 10°C
Temperature of hot water is 60°C
• We know that,
• Heat gain = Heat loss
40×1×(60-T) = 100×1×(T-Tc)
40×60 - 40×T = 100×10
40T = 2400 - 1000
= 1400
• T = 35°C
• Intial temperature, Tc = T - 10°C = 35°C - 10°C = 25°C
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