40g of solid which is 60% sodium trioxocarbonate IV was heated until there was no further evolution of carbon IV oxide gas. The equation of the reaction is:
2NaHCO3>NaClO3+H2O+CO2
1.What is the mass of sodium trioxocarbonate IV in the solid?
2.calculate the mass of sodium trioxocarbonate IV and;
ii. Water, that is produced in the reaction Na=23,H=1,C=12,O=16.
Answers
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1.1.1: Apply the mole concept to substances.Edit
A mole is equivalent to 6.022 x 1023 (Avogadro's constant) units. Chemists refer to a mole of something much as we refer to a dozen eggs; it is a convenient unit for counting. The periodic table provides molar masses, i.e. the number of grams of an element equivalent to one mole of atoms of that specific element. This can be extrapolated to molecules of known molecular formula.
1.1.2: Determine the number of particles and the amount of substance (in moles).Edit
Number of moles = mass / molar mass (Usually found on periodic table). The coefficients in chemical equations give the molar ratios of reactants and products i.e. 2A + 3B → C. There is 2/3 as much A as B, and 3 times more B than C involved in the reaction. Assuming the reaction goes to completion, there must be 3/2 times as much B as A for neither to remain. If this ratio is not followed, one will be a limiting reactant, and so the reaction will have some of the other reactant left over when it completes.
1.2 FormulaEdit1.2.1: Define the term molar mass (M) and calculate the mass of one mole of a species.Edit
The molar mass (M) is the mass of one mole's worth of a substance. To find the atomic/molecular mass, multiply the amount of moles by the molar mass.
1.2.2: Atomic mass, Molecular Mass, Formula MassEdit
The molar mass can be found in the periodic table, and will give the mass for 1 mol of the species (or rather the average accounting for different isotopes and their relative abundance).
1.2.3: Define the terms relative molecular mass (Mr) and relative atomic mass (Ar)Edit
Mr is the ratio between the molar masses of two species. Ar is the ratio of the number of atoms between two species.
Since sodium carbonate is a weak base you are probably mainly going to produce the monosodium citrate. (remember each time you remove a proton from one of the carboxylic acid groups it will substantially lower the pKa of the remaining groups! (i.e the acidity of each of the carboxylic acid groups are not the same.)
1 Na2CO3 is prepared in the laboratory by passing carbon iv oxide co2 through a solution of sodium hydroxide NaOH. The reaction between these two chemicals produces both sodium trioxocarbonate iv Na2CO3 and sodium hydrogen trioxocarbonate iv NaHCO3.
2 Solution is HCl. B is a solution of ... Solution A is HCl. B is a solution of sodium trioxocarbonate(IV). of B is titrated against A using methyl orange as indicator. of A is used in titration. Calculate the mass of sodium trioxocabonate(IV) present in one of the solution B. [Na = 23, C = 12, O = 16]
molar concentration of acid, CA =
volume of acid, VA =
molar concentration of base, CB=?
volume of base, VB =
from equation of reaction:
we can see that
a/b = mole ratio of acid to base
a:b = 2:1
molar mass of
The problem now is how do I get the mass of sodium trioxocarbonate(IV) present in one of the solution