Chemistry, asked by renuka7735, 1 year ago

40gm of naoh are presented in one decilitre of solution calculate the mole fraction naoh


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Answered by chris7833
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Shayan Alam asked in Chemistry

4.0g of NaOH is contained in one decilitre of a solution. Calculate the following in the solution 

1)MOLe Fraction of NaOH 

2)Molality of NaOH 

3)Molarity of NaOH 

Density of NaOH solution is 1.038g/cm3

I Think You Missed That It Is not 40g but 4.0 g.God bless you⛪

= Mass = density × volume

Mass of 0.1 l NaOH solution = 1.038 g/cm3 ×100 cm3 = 103.8 g

1) 4 g of NaOH is present in 103.8 g of solution.

Therefore solvent is 99.8 g.

No of moles of NaOH = 

440=0.1 mol

No of moles of water = 

99.818=5.44 mol

Total no of moles = 0.1 + 5.544 = 5.644 moles

Mole fraction of NaOH = No of moles of NaOH Total no of moles=0.15.644=0.0177

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