(41)^16-(14)^16 is multiple of
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Expressing 1485 as 27 x 55, and 41^16 - 14^16 being divisible by both 27 and 55, we can conclude that 41^16 - 14^16 is a multiple of 1485.
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Answer:1485
41^16 - 14^16 is a large number and 1485 can't be it's multiple. It must be the other way round.
Step-by-step explanation:
NOW :
a^n - b^n is always divisible by (a - b) and by (a + b) when n is even.
=> 41^16 - 14^16 is always divisible by 41 - 14 = 27 and 41 + 14 = 55.
Expressing 1485 as 27 x 55, and 41^16 - 14^16 being divisible by both 27 and 55, we can conclude that 41^16 - 14^16 is a multiple of 1485.
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