41. (4) Energy Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the velocity of B when angle a= 60°? α А (1) 10 m/s (3) 5.8 m/s (2) 9.8 m/s (4) 17.3 m/s
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Answer:
Given,
Velocity=10m/s α=60
0
L
2
=x
2
+y
2
On differentiating we get,
0=2x
dt
dx
+2y
dt
dy
The Velocity of A =
dt
dx
=−10m/s
Thus the velocity of particle B is:
dt
dy
=
y
−x
dt
dx
=cot60
0
×10=
3
1
×10=5.8m/s
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