Question

41
4. If n[p(A)]+n[P(B)]= 1025, n(A) < n(B), then n(A) =
1) 1
2) 2
3) 0
4) 4​

Answer 1

We have:

n(P(A))+n(P(B) = 1025

Where,  n(A) < n(B)

We have to find the value of n(A) = ?

Solution:

∴ n(P(A))+n(P(B) = 1025

n(A) = 2

Beacuse, it is a number of functions in the sunset.

∴ The value of n(A) = 2

Thus, the value of n(A) is "equal to 2".

Thus, the required "option 2) 2" is correct.

Answer 2

$Given \: n[P(A)] + n[P(B)] = 1025$

$\implies n[P(A)] + n[P(B)] = 1 + 1024\\= 2^{0} + 2^{10}\\= 2^{n(A)} + 2^{n(B)}$

$n(A) = 0 \: and \: n(B) = 10$

Therefore.,

$\red { n(A) } \green { = 0}$

$Option \:pink { (3) } \: is \: correct.$

•••♪