Question

41 (a) An electric bulb is connected to a 220V generator. The current is 0.50A.What is the

power of the bulb?

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Answer 1

Given :-

Voltage of the electric bulb = 220 V

Current of the electric bulb = 0.50 A

To Find :-

The power of the bulb.

Analysis :-

Here we are given with the voltage and the current of the electric bulb.

In order to find the power of the bulb substitute the given values in the question such that power is equal to voltage multiplied by the current of the electric bulb.

Solution :-

We know that,

• p = Power
• i = Current
• v = Voltage

Using the formula,

$\underline{\boxed{\sf Power = Voltage \times Current }}$

Given that,

Voltage (v) = 220 V

Current (i) = 0.50 A

Substituting their values,

⇒ p = vi

⇒ p = 220 × 0.50

⇒ p = 110 W

Therefore, the power of the electric bulb is 110 W.

Additional knowledge :-

Electric power:

Electric power is defined as the rate in which the energy is transformed into an electrical circuit.

Electric power is denoted using the letter 'P'.

The SI unit of electric power is Watt (W) or Joule per second (J/s).

In order to find the electric power, simply multiply the voltage and the current which is given in the question.

Formula: Power = Voltage × Current

Where,

➡ P : Power.

➡ V : Potential difference in the circuit

➡ I : Electric current

Answer 2

Answer:

Given :-

• Current = 0.5 A
• Voltage of bulb = 220 V

To Find :-

Power of bulb

Solution :-

As we know that power is defined as the product of current and voltage.

Therefore,

$\huge \star \small \bf {POWER = CURRENT \times VOLTAGE}$

It can be also written as

$\huge \star \huge\bf \: P = iv$

Here,

P = Power

I = Current

V = Voltage

Putting values

$\sf \: power \: = 0.5 \times 220$

$\sf \: power \: = 110 W$