Math, asked by ntikarya06, 4 months ago

41. A, B and C can do a piece of work in 16,32 and 48 days
respectively, they start working together but C leaves
after working 4 days and B, 2 days before the
completion of work. Find in how many days the work
was finished?
a) 5 days b) 8 days
c) 10 days d) 12 days​

Answers

Answered by taj312
0

Step-by-step explanation:

The work is finished in 12 days.

Answered by vivekanandrai138
1

The work is finished in 12 days.

Step-by-step explanation:

Let the work done by A in x days.

Let the work done by B in x-8 days.

Let the work done by C in x-6 days.

Since we have given that

Number of days in which A can finish his work = 16 days

Number of days in which B can finish his work = 32 days

Number of days in which C can finish his work = 48 days

According to question,

\begin{gathered}\frac{x}{16}+\frac{x-8}{32}+\frac{x-6}{48}=1\\\\L.C.M.\ of\ 16,32,48=96\\\\\frac{4x+3(x-8)+2(x-6)}{96}=1\\\\6x+3x-24+2x-12=96\\\\11x-36=96\\\\11x=96+36\\\\11x=132\\\\x=\frac{132}{11}\\\\x=12\end{gathered}

16

x

+

32

x−8

+

48

x−6

=1

L.C.M. of 16,32,48=96

96

4x+3(x−8)+2(x−6)

=1

6x+3x−24+2x−12=96

11x−36=96

11x=96+36

11x=132

x=

11

132

x=12

Hence, the work is finished in 12 days.

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