Question

41. A bag contains 5 white and 3 black balls and 4 balls are
successively drawn out and not replaced. The probability
that they are alternately of different colours, is
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Answer 1

Answer-

Probability of getting alternating colors when the first ball is white = 5/8 X 3/7 X 4/6 X 2/5 = 1/14

Probability of getting alternating colors when the first ball is black=  3/8 X 5/7 X 2/6 X 4/5 = 1/14

⇒Probability of getting balls of alternating color = 1/14 X 1/14 = 1/7

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