Question

41) A resistance of 20 ohms and one of 80 ohms are

arranged in series across 220 volt supply. What will be the

heat in joules produced by this combination in 10

minutes?

A) 48400 J

B) 22000 J

C) 290400 J

D) 4840 J​

Answer 1

Explanation:

h=i^2rt

where, i=current r=equivalent resistance. t=time

r=r1+r2

r=20+80

r=100ohm

by ohms law,

v=ir

220=i×100

i=220/100

i=2.2A

t= 10 min

t= 10×60=600 sec

h=i^2rt

h=2.2^2 ×100×600

h=4.84×60000

h=290400 j

so the correct answer is C)290400 j

Answer 2

Answer:

Answer is C

Explanation:

HOPE IT WILL BE BETTER FOR YOUU