Question

41 : How many ways are there to distribute 10
different books among 15 people if no person is to
receive more than 1 book?
3605705234
P(15,10)
1510
P(15,5)​

Answer 1

To get more sight on this divide e.g. 3 books among 2 persons and have a close look on what happens. – drhab Jul 8 '19 at 9:16  

10P5 is the answer on the question: "on how many ways can I divide 5 different books among 10 persons in such a way that a person will receive at most one book?" 10C5 is the answer on the question: "on how many ways can I divide 5 equal books among 10 persons in such a way that a person will receive at most one book?" – drhab Jul 8 '19 at 9:34

yes i tried to do it with 3 books 2 people and heres what i came up with just by doing brute force calculation: my first answer was 9 and what i did was setting 2 people up and just noting down how all the combinations (p1 has 0 books, p2 has 0 books and successively incrementing). This means that to get 2^3, we are ignoring the combination where both people dont have any books. Then i tried to put combinations for the books they could choose i.e. instead of p1 has 1 book, p2 has 1 book; now p1 has 3C1 books and p2 has 2C1 books which gets me 27. Is there a better way to do this? – Chowder