Question

41/ If a point A (0,2) is equidistant from the points B (3.p) and C(p,5), then find the value of p​

Answer 1

Thank me Dear student❤

Answer 2

Given,

Coordinates of point A = (0,2)

Coordinates of point B = (3,p)

Coordinates of point C = (p,5)

B and C are equidistant from A.

To find,

The numerical value of "p".

Solution,

Let us, calculate the distance between point A and point B, and the distance between point A and point C.

Distance between A and B = ✓(3-0)²+(p-2)² = ✓9+(p-2)²

Distance between A and C = ✓(p-0)²+(5-2)² = ✓p²+9

Now, B and C are equidistant from A,

So,

✓9+(p-2)² = ✓p²+9

9 + (p-2)² = p²+9

9+ p²- 4p +4 = p²+9

13+p²-4p = p²+9

p²-4p-p² = 9-13

-4p = - 4

p = 1

Hence,the value of p is 1.