41. If n(u) = 500, n(A) = 150, n(B) = 300 and n(AB) = 70, then value of n(A-B) = ........
A. 300
B. 120
C. 360
D. 80
T
Answers
Answer:
Answer D . 80
Step-by-step explanation:
Universal set U contains 500 ...as n(U) = 500.
The sets A and B are part of the Universal set U. The are overlapping and have a non zero intersection.
Cardinality of A = n (A) = 150
n (B) = 300
Given also the cardinality of the set of intersection of A and B:
n( A ∩ B) = n (AB) = 70
We know that the set A - B = A - A ∩ B
So cardinality of A - B = n(A) - n ( A∩ B)
ie., n (A - B) = 150 - 70
= 80
answer.
we can also find n (B - A ) = n (B) - n( A ∩ B) = 300 - 70 = 230
we can find n (A') = n(U) - n(A) = 350
n (B') = n(U) - n(B) = 200
n (A U B) = n (A) + n(B) - n (A∩B) = 150 + 300 - 70 = 380
Step-by-step explanation:
A-B = A ∩ (¬ B)
The number of items in ...
A ... 150
A ∩ B ... 70
the elements in A ∩ (¬ B) are the elements of A after you remove the elements in A ∩ B, so subtract the two numbers to get the answer.