Question

41. If x2 + y2 = 7 xy; then show that 2
log(x+y) = log x + log y + 2 log 3​

Answer 1

Answer:(x+y)^2-2xy=7xy

(x+y)^2=9xy

log((x+y)^2)=log(((3)^2)xy)

2log(x+y)=logx+logy+2log3

hope it helps u ✌✌