Question

41. Side of a square increased by 10%, find the
increase in area.
Full process​

Answer 1

Let

the Size Of a Square is ' a '

Now 10% of a

$= > \frac{10}{100} \times a = \frac{a}{10}$

Total Length of Side

$= > \frac{a}{10} + a \: = \frac{11a}{10}$

$area \: = {(side)}^{2} \\ \\ = {( \frac{11a}{10} )}^{2} = \frac{121 {a}^{2} }{100}$