(41.)The difference of the compound interest and the simple interest on 60000 at 6% annually for 2 yr will be ?
(42.) The compound interest on 350 for 1 year at 4% per annum, the interest being payable half yearly, will be ?
Answers
Answer: 1) Given Rate of interest is r=10%=0.1
Principal Amount is A=6,000
Time is t=2 years
Interest is compounded yearly once ⟹n=1
Amount =P(1+
n
r
)
nt
=6000×(1+0.1)
2
=7260
Interest is A−P=7260−6000=1260
Simple Interest is
100
6000×10×2
=1200
Difference between simple interest and compound interest is 1260−1200=60
2) Given,
P = Rs.350
T = 1 year = 2 half years
R = 4% p.a. = 4/2 per half year = 2% per half year
A = P (1 + R/100)^t
A = 350 (1 + 2/100)^2
= 350 (1 + 1/50)^2
= 350 (51/50)^2
= 350 (2601/2500)
= 91035/250
= Rs. 364.14
Compound Interest = Amount - Principal
= 364.14 - 350 = Rs.14.14
Step-by-step explanation:
Answer:
Compund Interest A= P(1 + r/n) (nt)
Simple Interest =P×R×T/100
6000×6×2/100
=720
Step-by-step explanation:
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