Chemistry, asked by RDatta, 1 year ago

41. The standard reduction potential of Pb and Zn
electrodes are -0.126 and -0.763 volts
respectively. The e.m.f. of the cell
Zn | Zn2+ (0.1 M) || Pb2+ (1 M)| Pb is
(1) 0.637 V
(2) < 0.637 V
(3) > 0.637 V (4) 0.889​

Answers

Answered by Anonymous
35

welcome to the concept of emf

in this question concentration is also given so we use nerset equation .

E ° cell = 0.736-0.1236 = 0.61

Q= 10^-1 and n =2

now by nernst equation

E cell = 0.64

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Answered by Prakshi1415
3

Answer:

Cell potential = 0.64 V

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