Question

41.
Two bodies move in the same straight
line at the same instant of time from
the same origin. The first body moves
with a constant velocity of 40 m/sec
and second starts with a constant
acceleration of 4 m/sec?. The time that
elapses before the second body
catches the first body is,
(A) 10 sec
(B) 20 sec
(C) 30 sec
(D) 15 sec
​

Answer 1

Answer:

20 sec

Explanation:

Considering the time be=t

first body moves with constant velocity of 40 m/s

so first body travels distance= 40t

Second body

starts with constant acceleration (a)=4m/s

intial velocity (u)=0 m/s

traveling time(t)=t

so traveling distance=ut+1/2at^2

=0×t+1/2×4×t^2

=0+2×t^2

=2×t^2

now

2×t^2=40t

t=20

Answer 2

Answer:

t=20 seconds

Explanation:

hope it helps you