Question

41) What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain – x2 - y2 +
6xy + 20

Answer 1

Answer:

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Step-by-step explanation:

Let q should be subtracted.

Then according to question,

3x^2 – 4y^2 + 5xy + 20 - q = -x^2 – y^2 +6xy + 20

⇒ q = 3x^2 – 4y^2 + 5xy + 20 -  ( - x^2 - y^2 + 6xy + 20)

⇒ q=3x^2 – 4y^2 + 5xy + 20+ x^2 + y^2 – 6xy – 20

⇒ q = 3x^2 + x^2 – 4y^2 + y^2 + 5xy - 6xy + 20 – 20

⇒  q = 4x^2 – 3y^2 – xy + 0

Hence, 4x^2 – 3y^2 - xy should be subtracted.